Armstrong Number In Java Example

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import java.util.Scanner;

public class JavaArmstrongNumber {
	public static void main(String args[]) {
		int n, sum = 0, temp, remainder, digits = 0;

		Scanner in = new Scanner(System.in);
		System.out.println("Input a number to check if it is an Armstrong number");
		n = in.nextInt();
		temp = n;

		while (temp != 0) {
			digits++;
			temp = temp / 10;
		}
		temp = n;
		while (temp != 0) {
			remainder = temp % 10;
			sum = sum + power(remainder, digits);
			temp = temp / 10;
		}

		if (n == sum)
			System.out.println(n + " is an Armstrong number.");
		else
			System.out.println(n + " is not an Armstrong number.");
	}

	static int power(int n, int r) {
		int c, p = 1;

		for (c = 1; c <= r; c++)
			p = p * n;

		return p;
	}
}
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