Java StrictMath Floor() Method
Chapter:
Collections
Last Updated:
21-08-2017 15:37:43 UTC
Program:
/* ............... START ............... */
public class StrictMathFloor {
public static void main(String[] args) {
double d1 = 5.3, d2 = 7.8, d3 = 1.5;
double floorValue = StrictMath.floor(d1);
System.out.println("Floor value of " + d1 + " = " + floorValue);
floorValue = StrictMath.floor(d2);
System.out.println("Floor value of " + d2 + " = " + floorValue);
floorValue = StrictMath.floor(d3);
System.out.println("Floor value of " + d3 + " = " + floorValue);
}
}
/* ............... END ............... */
Output
Floor value of 5.3 = 5.0
Floor value of 7.8 = 7.0
Floor value of 1.5 = 1.0
Notes:
-
The java.lang.StrictMath.floor() method returns the largest (closest to positive infinity) double value that is less than or equal to the argument and is equal to a mathematical integer.
- If the argument value is already equal to a mathematical integer, then the result is the same as the argument.
- If the argument is NaN or an infinity or positive zero or negative zero, then the result is the same as the argument.
Tags
StrictMath Floor() Method, Java, Collection