Java Program To Find Special Characters In String

Chapter: String Handling Last Updated: 21-04-2016 14:57:13 UTC

Program:

            /* ............... START ............... */
                
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class JavaStringSpecialCharacter {
	public static void main(String[] args) {

		String string = "Java$example^fs#fff";

		Pattern pattern = Pattern.compile("[^a-z0-9 ]", Pattern.CASE_INSENSITIVE);
		Matcher matcher = pattern.matcher(string);

		System.out.println(string);
		int count = 0;
		while (matcher.find()) {
			count = count + 1;
			System.out.println("Position " + matcher.start() + ": " + string.charAt(matcher.start()));
		}
		System.out.println("There are " + count + " special characters");
	}
}
                /* ............... END ............... */
        

Output

Java$example^fs#fff
Position 4: $
Position 12: ^
Position 15: #
There are 3 special characters

Tags

Special Characters In String, Java

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