Java Program To Find Rectangle Perimeter
Chapter:
Math Class
Last Updated:
15-06-2016 19:37:20 UTC
Program:
/* ............... START ............... */
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class JavaRectanglePerimeterExample {
public static void main(String[] args) {
int width = 0;
int length = 0;
try {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
System.out.println("Please enter length of a rectangle");
length = Integer.parseInt(br.readLine());
// read the width from console
System.out.println("Please enter width of a rectangle");
width = Integer.parseInt(br.readLine());
} catch (NumberFormatException ne) {
System.out.println("Invalid value" + ne);
System.exit(0);
} catch (IOException ioe) {
System.out.println("IO Error :" + ioe);
System.exit(0);
}
int perimeter = 2 * (length + width);
System.out.println("Perimeter of a rectangle is " + perimeter);
}
}
/* ............... END ............... */
Output
Please enter length of a rectangle
10
Please enter width of a rectangle
20
Perimeter of a rectangle is 60
Tags
Find Rectangle Perimeter, Java, Math