Java Program To Find Rectangle Perimeter

Chapter: Math Class Last Updated: 15-06-2016 19:37:20 UTC

Program:

            /* ............... START ............... */
                
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class JavaRectanglePerimeterExample {

	public static void main(String[] args) {

		int width = 0;
		int length = 0;

		try {

			BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

			System.out.println("Please enter length of a rectangle");
			length = Integer.parseInt(br.readLine());

			// read the width from console
			System.out.println("Please enter width of a rectangle");
			width = Integer.parseInt(br.readLine());

		} catch (NumberFormatException ne) {
			System.out.println("Invalid value" + ne);
			System.exit(0);
		} catch (IOException ioe) {
			System.out.println("IO Error :" + ioe);
			System.exit(0);
		}

		int perimeter = 2 * (length + width);

		System.out.println("Perimeter of a rectangle is " + perimeter);
	}
}
                /* ............... END ............... */
        

Output

Please enter length of a rectangle
10
Please enter width of a rectangle
20
Perimeter of a rectangle is 60

Tags

Find Rectangle Perimeter, Java, Math

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