Java BorderLayout Example
Chapter:
Swing
Last Updated:
27-09-2016 16:11:04 UTC
Program:
/* ............... START ............... */
import java.awt.BorderLayout;
import java.awt.Container;
import javax.swing.JButton;
import javax.swing.JFrame;
public class JavaBorderLayoutExample {
public static void main(String[] args) {
JFrame frame = new JFrame("BorderLayout Test");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
Container container = frame.getContentPane();
container.add(new JButton("North"), BorderLayout.NORTH);
container.add(new JButton("South"), BorderLayout.SOUTH);
container.add(new JButton("East"), BorderLayout.EAST);
container.add(new JButton("West"), BorderLayout.WEST);
container.add(new JButton("Center"), BorderLayout.CENTER);
frame.pack();
frame.setVisible(true);
}
}
/* ............... END ............... */
Output
Notes:
-
The BorderLayout divides a container's space into five areas: north, south, east, west, and center.
- The BorderLayout class defines five constants to identify each of the five areas. The constants are NORTH, SOUTH, EAST, WEST, and CENTER.
- The default layout for the content pane of a JFrame is a BorderLayout.
Tags
BorderLayout, Java, Swing