Java Program To Reverse Digits Of Number Using While Loop

Chapter: Miscellaneous Last Updated: 16-12-2016 12:58:43 UTC

Program:

            /* ............... START ............... */
                
import java.io.*;

public class JavaReverseDigits {

	public static void main(String args[]) throws Exception {
		int num = 0, reverse, lastDigit;
		System.out.println("Enter an Integer");
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		num = Integer.parseInt(br.readLine());
		reverse = 0;
		while (num != 0) {
			lastDigit = num % 10;
			reverse = reverse * 10 + lastDigit;
			num = num / 10;
		}
		System.out.println("Reversed Number : " + reverse);
	}
}
                /* ............... END ............... */
        

Output

Enter an Integer
383899
Reversed Number : 998383

Notes:

  • Algorithm to reverse digits of a number
  • Get the least significant digit(right most digit or last digit) of the number lastDigit = number%10.
  • Append it at the end of reverse number reverse = (reverse * 10) + lastDigit.
  • Remove right most digit from number number = number/10.
  • Repeat this process till number is greater than zero.

Tags

Reverse Digits Of Number Using While Loop, Java, Miscellaneous

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