Chapter: Date and Time Last Updated: 22-06-2023 14:07:27 UTC

Program:

` ````
/* ............... START ............... */
import java.util.Scanner;
public class LeapYearChecker {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("Enter a year: ");
int year = scanner.nextInt();
if (isLeapYear(year)) {
System.out.println(year + " is a leap year.");
} else {
System.out.println(year + " is not a leap year.");
}
}
public static boolean isLeapYear(int year) {
// Leap year is divisible by 4 but not divisible by 100
// unless it is divisible by 400
if (year % 4 == 0 && (year % 100 != 0 || year % 400 == 0)) {
return true;
}
return false;
}
}
/* ............... END ............... */
```

Output

Input: 2020 Output: 2020 is a leap year. Input: 2021 Output: 2021 is not a leap year. Input: 1900 Output: 1900 is not a leap year. Input: 2000 Output: 2000 is a leap year. Input: 2024 Output: 2024 is a leap year.

Notes:

- In this program, we use a Scanner to read input from the user. The isLeapYear method takes an integer year as input and returns true if it is a leap year, and false otherwise. The logic for checking leap year is as follows:
- A year is a leap year if it is divisible by 4.
- However, if the year is divisible by 100, it is not a leap year, unless it is divisible by 400.
- The isLeapYear method implements this logic and returns the result.
- In the main method, we prompt the user to enter a year, and then call the isLeapYear method to check whether it is a leap year or not. The program then prints the appropriate message based on the result.

Tags

Leap year program in Java using Scanner # Write A Program To Check Leap Year In Java # Java Program to Check Leap Year

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