Java Program To Calculate Time Difference In Seconds

Chapter: Date and Time Last Updated: 20-09-2023 14:48:20 UTC

Program:

            /* ............... START ............... */
                

import java.time.LocalDateTime;
import java.time.Duration;

public class TimeDifferenceInSeconds {
    public static void main(String[] args) {
        // Create two LocalDateTime objects representing two different times
        LocalDateTime startTime = LocalDateTime.of(2023, 9, 20, 10, 0, 0); // Replace with your start time
        LocalDateTime endTime = LocalDateTime.of(2023, 9, 20, 12, 30, 0); // Replace with your end time

        // Calculate the time difference in seconds
        Duration duration = Duration.between(startTime, endTime);
        long secondsDifference = duration.getSeconds();

        System.out.println("Time difference in seconds: " + secondsDifference + " seconds");
    }
}

                /* ............... END ............... */
        

Output

Time difference in seconds: 9000 seconds

In this example, the program calculates the time difference in seconds between
 the start time and end time, which is 2 hours and 30 minutes, or 9000 seconds.

Notes:

• First we create two LocalDateTime objects, startTime and endTime, representing the two different times for which we want to calculate the time difference.
• Then we use the Duration.between() method to calculate the duration between the two LocalDateTime objects. This method returns a Duration object.
• In next step we extract the number of seconds from the Duration object using the getSeconds() method and store it in the secondsDifference variable.
• Finally, we print the time difference in seconds.
• Replace the values of startTime and endTime with your desired date and time values to calculate the time difference between them in seconds.

Tags

Java program to calculate time difference in seconds #How to calculate time difference in seconds in Java? #Java program to find time difference in seconds

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